7-3(c+1)=2(c-3)

Solution for 7-3(c+1)=2(c-3) equation:

Simplifying
7 + -3(c + 1) = 2(c + -3)

Reorder the terms:
7 + -3(1 + c) = 2(c + -3)
7 + (1 * -3 + c * -3) = 2(c + -3)
7 + (-3 + -3c) = 2(c + -3)

Combine like terms: 7 + -3 = 4
4 + -3c = 2(c + -3)

Reorder the terms:
4 + -3c = 2(-3 + c)
4 + -3c = (-3 * 2 + c * 2)
4 + -3c = (-6 + 2c)

Solving
4 + -3c = -6 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
4 + -3c + -2c = -6 + 2c + -2c

Combine like terms: -3c + -2c = -5c
4 + -5c = -6 + 2c + -2c

Combine like terms: 2c + -2c = 0
4 + -5c = -6 + 0
4 + -5c = -6

Add '-4' to each side of the equation.
4 + -4 + -5c = -6 + -4

Combine like terms: 4 + -4 = 0
0 + -5c = -6 + -4
-5c = -6 + -4

Combine like terms: -6 + -4 = -10
-5c = -10

Divide each side by '-5'.
c = 2

Simplifying
c = 2