7-3(x2)=(7-x)4-4x

Solution for 7-3(x2)=(7-x)4-4x equation:

7-3(x2)=(7-x)4-4x

We move all terms to the left:

7-3(x2)-((7-x)4-4x)=0

We add all the numbers together, and all the variables

-3x2-((-1x+7)4-4x)+7=0

We add all the numbers together, and all the variables

-3x^2-((-1x+7)4-4x)+7=0


We calculate terms in parentheses: -((-1x+7)4-4x), so:

(-1x+7)4-4x

We add all the numbers together, and all the variables

-4x+(-1x+7)4

We multiply parentheses

-4x-4x+28

We add all the numbers together, and all the variables

-8x+28

Back to the equation:

-(-8x+28)


We get rid of parentheses

-3x^2+8x-28+7=0

We add all the numbers together, and all the variables

-3x^2+8x-21=0

a = -3; b = 8; c = -21;
Δ = b2-4ac
Δ = 82-4·(-3)·(-21)
Δ = -188
Delta is less than zero, so there is no solution for the equation