7-3(y+6)+50=y-1

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Solution for 7-3(y+6)+50=y-1 equation: 



7-3(y+6)+50=y-1

We move all terms to the left:

7-3(y+6)+50-(y-1)=0

We add all the numbers together, and all the variables

-3(y+6)-(y-1)+57=0

We multiply parentheses

-3y-(y-1)-18+57=0

We get rid of parentheses

-3y-y+1-18+57=0

We add all the numbers together, and all the variables

-4y+40=0

We move all terms containing y to the left, all other terms to the right

-4y=-40

y=-40/-4

y=+10

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