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7-3/10x=x
We move all terms to the left:
7-3/10x-(x)=0
Domain of the equation: 10x!=0We add all the numbers together, and all the variables
x!=0/10
x!=0
x∈R
-1x-3/10x+7=0
We multiply all the terms by the denominator
-1x*10x+7*10x-3=0
Wy multiply elements
-10x^2+70x-3=0
a = -10; b = 70; c = -3;
Δ = b2-4ac
Δ = 702-4·(-10)·(-3)
Δ = 4780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4780}=\sqrt{4*1195}=\sqrt{4}*\sqrt{1195}=2\sqrt{1195}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-2\sqrt{1195}}{2*-10}=\frac{-70-2\sqrt{1195}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+2\sqrt{1195}}{2*-10}=\frac{-70+2\sqrt{1195}}{-20} $
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