7-3m+2(m-8)=2+5(4-m)

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Solution for 7-3m+2(m-8)=2+5(4-m) equation: 



7-3m+2(m-8)=2+5(4-m)

We move all terms to the left:

7-3m+2(m-8)-(2+5(4-m))=0

We add all the numbers together, and all the variables

-3m+2(m-8)-(2+5(-1m+4))+7=0

We multiply parentheses

-3m+2m-(2+5(-1m+4))-16+7=0



We calculate terms in parentheses: -(2+5(-1m+4)), so:

2+5(-1m+4)

determiningTheFunctionDomain
5(-1m+4)+2

We multiply parentheses

-5m+20+2

We add all the numbers together, and all the variables

-5m+22

Back to the equation:

-(-5m+22)



We add all the numbers together, and all the variables

-1m-(-5m+22)-9=0

We get rid of parentheses

-1m+5m-22-9=0

We add all the numbers together, and all the variables

4m-31=0

We move all terms containing m to the left, all other terms to the right

4m=31

m=31/4

m=7+3/4

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