7-3x+6x+1=4(7-x)-2(1-8x)

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Solution for 7-3x+6x+1=4(7-x)-2(1-8x) equation: 



7-3x+6x+1=4(7-x)-2(1-8x)

We move all terms to the left:

7-3x+6x+1-(4(7-x)-2(1-8x))=0

We add all the numbers together, and all the variables

-3x+6x-(4(-1x+7)-2(-8x+1))+7+1=0

We add all the numbers together, and all the variables

3x-(4(-1x+7)-2(-8x+1))+8=0



We calculate terms in parentheses: -(4(-1x+7)-2(-8x+1)), so:

4(-1x+7)-2(-8x+1)

We multiply parentheses

-4x+16x+28-2

We add all the numbers together, and all the variables

12x+26

Back to the equation:

-(12x+26)



We get rid of parentheses

3x-12x-26+8=0

We add all the numbers together, and all the variables

-9x-18=0

We move all terms containing x to the left, all other terms to the right

-9x=18

x=18/-9

x=-2

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