If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2*(3*x+2) = 7*(3*x+2);x
x
(x^2)/2
(x^4+2*x^2)/(3*x^3-x+1)
((2*x^2)/3)*x^3+x^4-x+1
0.2223/0.66669582
| (x^3)+(3x^2-x)-(6+5x)= | | 4*x-8=20 | | 6x-2(x-2)=4(x+1)+4 | | 2cosx/5=0 | | 20x^3/60x | | 7+9(4x-3)=88 | | 2(6x+4)-7(4+5x)=3 | | 4x+7+8x+11+90=180 | | 9t*3+t+5(t-9t*3)= | | -6=2cx | | 1/3x5/9=2/9 | | 1/3x5/9= | | 5x-1+5(7x+3)= | | 8(8+4r)-2(2r+2)=-52 | | 5a-4=3a+34 | | 5a-4=3a-34 | | =(3x-9)(3x-9)(3x-9)(3x-9) | | 0=7x^4-2x^2+1 | | -2p+7=-6 | | 0.40x+0.05(2-x)=0.10(22) | | f(x)=3x^2+4x-10 | | 2-(x-11)=5(x+7) | | 5x+36=96 | | -1.54=x-2.9 | | 5-3x=2(x+10) | | 2-(x-8)=5(x+11) | | 30x^2+17= | | 1+8(-2+3)=-(3z-1)-7 | | (x)=2x^3+x-5 | | log3^1/27 | | log(x-5)=4 | | ln(x-7)=-4 |