7-4(2x-5)+3(x-8)=0

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Solution for 7-4(2x-5)+3(x-8)=0 equation: 



7-4(2x-5)+3(x-8)=0

We multiply parentheses

-8x+3x+20-24+7=0

We add all the numbers together, and all the variables

-5x+3=0

We move all terms containing x to the left, all other terms to the right

-5x=-3

x=-3/-5

x=3/5

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