7-4(2x-5)+3(x-8)=0

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Solution for 7-4(2x-5)+3(x-8)=0 equation:



7-4(2x-5)+3(x-8)=0
We multiply parentheses
-8x+3x+20-24+7=0
We add all the numbers together, and all the variables
-5x+3=0
We move all terms containing x to the left, all other terms to the right
-5x=-3
x=-3/-5
x=3/5

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