7-4(3x+5)=3(2-3x)-17

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Solution for 7-4(3x+5)=3(2-3x)-17 equation: 



7-4(3x+5)=3(2-3x)-17

We move all terms to the left:

7-4(3x+5)-(3(2-3x)-17)=0

We add all the numbers together, and all the variables

-4(3x+5)-(3(-3x+2)-17)+7=0

We multiply parentheses

-12x-(3(-3x+2)-17)-20+7=0



We calculate terms in parentheses: -(3(-3x+2)-17), so:

3(-3x+2)-17

We multiply parentheses

-9x+6-17

We add all the numbers together, and all the variables

-9x-11

Back to the equation:

-(-9x-11)



We add all the numbers together, and all the variables

-12x-(-9x-11)-13=0

We get rid of parentheses

-12x+9x+11-13=0

We add all the numbers together, and all the variables

-3x-2=0

We move all terms containing x to the left, all other terms to the right

-3x=2

x=2/-3

x=-2/3

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