7-4(3x-2)=3(x-5)

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Solution for 7-4(3x-2)=3(x-5) equation: 



7-4(3x-2)=3(x-5)

We move all terms to the left:

7-4(3x-2)-(3(x-5))=0

We multiply parentheses

-12x-(3(x-5))+8+7=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We add all the numbers together, and all the variables

-12x-(3x-15)+15=0

We get rid of parentheses

-12x-3x+15+15=0

We add all the numbers together, and all the variables

-15x+30=0

We move all terms containing x to the left, all other terms to the right

-15x=-30

x=-30/-15

x=+2

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