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7-4(3x-2)=3(x-5)
We move all terms to the left:
7-4(3x-2)-(3(x-5))=0
We multiply parentheses
-12x-(3(x-5))+8+7=0
We calculate terms in parentheses: -(3(x-5)), so:We add all the numbers together, and all the variables
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
-12x-(3x-15)+15=0
We get rid of parentheses
-12x-3x+15+15=0
We add all the numbers together, and all the variables
-15x+30=0
We move all terms containing x to the left, all other terms to the right
-15x=-30
x=-30/-15
x=+2
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