7-4(3x-5)-6x=1/3(9x+6)

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Solution for 7-4(3x-5)-6x=1/3(9x+6) equation: 



7-4(3x-5)-6x=1/3(9x+6)

We move all terms to the left:

7-4(3x-5)-6x-(1/3(9x+6))=0



Domain of the equation: 3(9x+6))!=0

x∈R



We add all the numbers together, and all the variables

-6x-4(3x-5)-(1/3(9x+6))+7=0

We multiply parentheses

-6x-12x-(1/3(9x+6))+20+7=0

We multiply all the terms by the denominator


-6x*3(9x+6))-12x*3(9x+6))-(1+20*3(9x+6))+7*3(9x+6))=0

Wy multiply elements

-54x^3(9+6))-(1+20*3(9x+6))+7*3(9x+6))=0

We do not support expression: x^3(9

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