7-4(4a+1)=8+a

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Solution for 7-4(4a+1)=8+a equation:



7-4(4a+1)=8+a
We move all terms to the left:
7-4(4a+1)-(8+a)=0
We add all the numbers together, and all the variables
-4(4a+1)-(a+8)+7=0
We multiply parentheses
-16a-(a+8)-4+7=0
We get rid of parentheses
-16a-a-8-4+7=0
We add all the numbers together, and all the variables
-17a-5=0
We move all terms containing a to the left, all other terms to the right
-17a=5
a=5/-17
a=-5/17

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