7-4(x+3)-5=7+2(4-2x)-16

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Solution for 7-4(x+3)-5=7+2(4-2x)-16 equation: 


Simplifying
7 + -4(x + 3) + -5 = 7 + 2(4 + -2x) + -16

Reorder the terms:
7 + -4(3 + x) + -5 = 7 + 2(4 + -2x) + -16
7 + (3 * -4 + x * -4) + -5 = 7 + 2(4 + -2x) + -16
7 + (-12 + -4x) + -5 = 7 + 2(4 + -2x) + -16

Reorder the terms:
7 + -12 + -5 + -4x = 7 + 2(4 + -2x) + -16

Combine like terms: 7 + -12 = -5
-5 + -5 + -4x = 7 + 2(4 + -2x) + -16

Combine like terms: -5 + -5 = -10
-10 + -4x = 7 + 2(4 + -2x) + -16
-10 + -4x = 7 + (4 * 2 + -2x * 2) + -16
-10 + -4x = 7 + (8 + -4x) + -16

Reorder the terms:
-10 + -4x = 7 + 8 + -16 + -4x

Combine like terms: 7 + 8 = 15
-10 + -4x = 15 + -16 + -4x

Combine like terms: 15 + -16 = -1
-10 + -4x = -1 + -4x

Add '4x' to each side of the equation.
-10 + -4x + 4x = -1 + -4x + 4x

Combine like terms: -4x + 4x = 0
-10 + 0 = -1 + -4x + 4x
-10 = -1 + -4x + 4x

Combine like terms: -4x + 4x = 0
-10 = -1 + 0
-10 = -1

Solving
-10 = -1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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