7-4d(1d-3)=23

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Solution for 7-4d(1d-3)=23 equation:



7-4d(1d-3)=23
We move all terms to the left:
7-4d(1d-3)-(23)=0
We add all the numbers together, and all the variables
-4d(d-3)+7-23=0
We add all the numbers together, and all the variables
-4d(d-3)-16=0
We multiply parentheses
-4d^2+12d-16=0
a = -4; b = 12; c = -16;
Δ = b2-4ac
Δ = 122-4·(-4)·(-16)
Δ = -112
Delta is less than zero, so there is no solution for the equation

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