7-4x/7=3-(x-4)

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Solution for 7-4x/7=3-(x-4) equation:



7-4x/7=3-(x-4)
We move all terms to the left:
7-4x/7-(3-(x-4))=0
We multiply all the terms by the denominator
-4x-((3-(x-4)))*7+7*7=0
We add all the numbers together, and all the variables
-4x-((3-(x-4)))*7+49=0
We move all terms containing x to the left, all other terms to the right
-4x-((3-(x-4)))*7=-49

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