7-4z=2(2z+3)

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Solution for 7-4z=2(2z+3) equation: 



7-4z=2(2z+3)

We move all terms to the left:

7-4z-(2(2z+3))=0



We calculate terms in parentheses: -(2(2z+3)), so:

2(2z+3)

We multiply parentheses

4z+6

Back to the equation:

-(4z+6)



We get rid of parentheses

-4z-4z-6+7=0

We add all the numbers together, and all the variables

-8z+1=0

We move all terms containing z to the left, all other terms to the right

-8z=-1

z=-1/-8

z=1/8

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