7-5(2r+5)=2(3+7r)

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Solution for 7-5(2r+5)=2(3+7r) equation: 



7-5(2r+5)=2(3+7r)

We move all terms to the left:

7-5(2r+5)-(2(3+7r))=0

We add all the numbers together, and all the variables

-5(2r+5)-(2(7r+3))+7=0

We multiply parentheses

-10r-(2(7r+3))-25+7=0



We calculate terms in parentheses: -(2(7r+3)), so:

2(7r+3)

We multiply parentheses

14r+6

Back to the equation:

-(14r+6)



We add all the numbers together, and all the variables

-10r-(14r+6)-18=0

We get rid of parentheses

-10r-14r-6-18=0

We add all the numbers together, and all the variables

-24r-24=0

We move all terms containing r to the left, all other terms to the right

-24r=24

r=24/-24

r=-1

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