7-5(2x-1)=3(3x+4)+5

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Solution for 7-5(2x-1)=3(3x+4)+5 equation: 



7-5(2x-1)=3(3x+4)+5

We move all terms to the left:

7-5(2x-1)-(3(3x+4)+5)=0

We multiply parentheses

-10x-(3(3x+4)+5)+5+7=0



We calculate terms in parentheses: -(3(3x+4)+5), so:

3(3x+4)+5

We multiply parentheses

9x+12+5

We add all the numbers together, and all the variables

9x+17

Back to the equation:

-(9x+17)



We add all the numbers together, and all the variables

-10x-(9x+17)+12=0

We get rid of parentheses

-10x-9x-17+12=0

We add all the numbers together, and all the variables

-19x-5=0

We move all terms containing x to the left, all other terms to the right

-19x=5

x=5/-19

x=-5/19

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