7-5(3x-4)=3(x-2)

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Solution for 7-5(3x-4)=3(x-2) equation:



7-5(3x-4)=3(x-2)
We move all terms to the left:
7-5(3x-4)-(3(x-2))=0
We multiply parentheses
-15x-(3(x-2))+20+7=0
We calculate terms in parentheses: -(3(x-2)), so:
3(x-2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
We add all the numbers together, and all the variables
-15x-(3x-6)+27=0
We get rid of parentheses
-15x-3x+6+27=0
We add all the numbers together, and all the variables
-18x+33=0
We move all terms containing x to the left, all other terms to the right
-18x=-33
x=-33/-18
x=1+5/6

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