7-5(4f+12)+12f+20=68

Simple and best practice solution for 7-5(4f+12)+12f+20=68 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 7-5(4f+12)+12f+20=68 equation: 



7-5(4f+12)+12f+20=68

We move all terms to the left:

7-5(4f+12)+12f+20-(68)=0

We add all the numbers together, and all the variables

12f-5(4f+12)-41=0

We multiply parentheses

12f-20f-60-41=0

We add all the numbers together, and all the variables

-8f-101=0

We move all terms containing f to the left, all other terms to the right

-8f=101

f=101/-8

f=-12+5/8

See similar equations:

| 4x^+7x=2 | | 15x-13=30 | | -8b+-8=-80 | | 1/4x^2–8x+64=0 | | -42=n/10+-37 | | p-10=98 | | 1+4p=37 | | 8(d+2)=40 | | 2/3​b+5=20−b | | n+54=32 | | 14,5+70d÷5=-13,5 | | 5+7x=6x=25 | | 23=u/7+22 | | 9x^2-1-(3x-2)^2=0 | | 12/2=x/1 | | 7-6x-3=-39+3x-11 | | 81m=9 | | 121-16t^2=0 | | m-98=-76 | | -8)-5=9(x+2)+1 | | 7-6x-3=39+3x-11 | | 7(x+2)-7=7x-2 | | 3x^-6x-9=0 | | 78-k=-90 | | 15+8-5(c=7) | | r^2+11r-26=0 | | (-2x+7)+(5x+1)=1 | | r^2+11r+26=0 | | 4+0,1b=6 | | 6x+11=8x-15 | | 78-k=90 | | 2x+10=5x+40 |

Equations solver categories