7-5=1/3(x+12)

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Solution for 7-5=1/3(x+12) equation: 



7-5=1/3(x+12)

We move all terms to the left:

7-5-(1/3(x+12))=0



Domain of the equation: 3(x+12))!=0

x∈R



We add all the numbers together, and all the variables

-(1/3(x+12))+2=0

We multiply all the terms by the denominator


-(1+2*3(x+12))=0



We calculate terms in parentheses: -(1+2*3(x+12)), so:

1+2*3(x+12)

determiningTheFunctionDomain
2*3(x+12)+1

Wy multiply elements

6x(x+1

Back to the equation:

-(6x(x+1)





We calculate terms in parentheses: -(6x(x+1), so:

6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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6x(x+1





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