7-6(1+4y)=32

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Solution for 7-6(1+4y)=32 equation:



7-6(1+4y)=32
We move all terms to the left:
7-6(1+4y)-(32)=0
We add all the numbers together, and all the variables
-6(4y+1)+7-32=0
We add all the numbers together, and all the variables
-6(4y+1)-25=0
We multiply parentheses
-24y-6-25=0
We add all the numbers together, and all the variables
-24y-31=0
We move all terms containing y to the left, all other terms to the right
-24y=31
y=31/-24
y=-1+7/24

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