7-6(c-1)+3(3-4c)=7(7c-4)

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Solution for 7-6(c-1)+3(3-4c)=7(7c-4) equation: 



7-6(c-1)+3(3-4c)=7(7c-4)

We move all terms to the left:

7-6(c-1)+3(3-4c)-(7(7c-4))=0

We add all the numbers together, and all the variables

-6(c-1)+3(-4c+3)-(7(7c-4))+7=0

We multiply parentheses

-6c-12c-(7(7c-4))+6+9+7=0



We calculate terms in parentheses: -(7(7c-4)), so:

7(7c-4)

We multiply parentheses

49c-28

Back to the equation:

-(49c-28)



We add all the numbers together, and all the variables

-18c-(49c-28)+22=0

We get rid of parentheses

-18c-49c+28+22=0

We add all the numbers together, and all the variables

-67c+50=0

We move all terms containing c to the left, all other terms to the right

-67c=-50

c=-50/-67

c=50/67

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