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7/(2x-3)=4/(x+5)
We move all terms to the left:
7/(2x-3)-(4/(x+5))=0
Domain of the equation: (2x-3)!=0
We move all terms containing x to the left, all other terms to the right
2x!=3
x!=3/2
x!=1+1/2
x∈R
Domain of the equation: (x+5))!=0We calculate fractions
x∈R
7x/((2x-3)*(x+5)))+(-(4*(2x-3))/((2x-3)*(x+5)))=0
We calculate terms in parentheses: -(4*(2x-3))/((2x-3)*(x+5))), so:We add all the numbers together, and all the variables
4*(2x-3))/((2x-3)*(x+5))
We multiply all the terms by the denominator
4*(2x-3))
We multiply parentheses
8x+
We add all the numbers together, and all the variables
8x
Back to the equation:
-(8x)
-8x+7x/((2x-3)*(x+5)))+(=0
We multiply all the terms by the denominator
-8x*((2x-3)*(x+5)))+(+7x=0
We add all the numbers together, and all the variables
7x-8x*((2x-3)*(x+5)))+(=0
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