7/(2x-5)=4/(x+1)

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Solution for 7/(2x-5)=4/(x+1) equation: 


D( x )

2*x-5 = 0

x+1 = 0

2*x-5 = 0

2*x-5 = 0

2*x-5 = 0 // + 5

2*x = 5 // : 2

x = 5/2

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:5/2) U (5/2:+oo)

7/(2*x-5) = 4/(x+1) // - 4/(x+1)

7/(2*x-5)-(4/(x+1)) = 0

7/(2*x-5)-4*(x+1)^-1 = 0

7/(2*x-5)-4/(x+1) = 0

(7*(x+1))/((2*x-5)*(x+1))+(-4*(2*x-5))/((2*x-5)*(x+1)) = 0

7*(x+1)-4*(2*x-5) = 0

27-x = 0

(27-x)/((2*x-5)*(x+1)) = 0

(27-x)/((2*x-5)*(x+1)) = 0 // * (2*x-5)*(x+1)

27-x = 0

27-x = 0 // - 27

-x = -27 // * -1

x = 27

x = 27

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