7/(2x-8)=3/(x-6)

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Solution for 7/(2x-8)=3/(x-6) equation: 



7/(2x-8)=3/(x-6)

We move all terms to the left:

7/(2x-8)-(3/(x-6))=0



Domain of the equation: (2x-8)!=0

We move all terms containing x to the left, all other terms to the right

2x!=8

x!=8/2

x!=4

x∈R





Domain of the equation: (x-6))!=0

x∈R



We calculate fractions


7x/((2x-8)*(x-6)))+(-(3*(2x-8))/((2x-8)*(x-6)))=0



We calculate terms in parentheses: -(3*(2x-8))/((2x-8)*(x-6))), so:

3*(2x-8))/((2x-8)*(x-6))

We multiply all the terms by the denominator


3*(2x-8))

We multiply parentheses

6x+

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We add all the numbers together, and all the variables

-6x+7x/((2x-8)*(x-6)))+(=0

We multiply all the terms by the denominator


-6x*((2x-8)*(x-6)))+(+7x=0

We add all the numbers together, and all the variables

7x-6x*((2x-8)*(x-6)))+(=0

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