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7/(3x+6)=1/9x
We move all terms to the left:
7/(3x+6)-(1/9x)=0
Domain of the equation: (3x+6)!=0
We move all terms containing x to the left, all other terms to the right
3x!=-6
x!=-6/3
x!=-2
x∈R
Domain of the equation: 9x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7/(3x+6)-(+1/9x)=0
We get rid of parentheses
7/(3x+6)-1/9x=0
We calculate fractions
63x/(27x^2+54x)+(-1*(3x+6))/(27x^2+54x)=0
We calculate terms in parentheses: +(-1*(3x+6))/(27x^2+54x), so:We multiply all the terms by the denominator
-1*(3x+6))/(27x^2+54x
We add all the numbers together, and all the variables
54x-1*(3x+6))/(27x^2
We multiply all the terms by the denominator
54x*(27x^2-1*(3x+6))
Back to the equation:
+(54x*(27x^2-1*(3x+6)))
63x+((54x*(27x^2-1*(3x+6))))*(27x^2+54x)=0
We calculate terms in parentheses: +((54x*(27x^2-1*(3x+6))))*(27x^2+54x), so:
(54x*(27x^2-1*(3x+6))))*(27x^2+54x
We add all the numbers together, and all the variables
54x+(54x*(27x^2-1*(3x+6))))*(27x^2
Back to the equation:
+(54x+(54x*(27x^2-1*(3x+6))))*(27x^2)
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