7/(4x+3)=2

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Solution for 7/(4x+3)=2 equation: 


D( x )

4*x+3 = 0

4*x+3 = 0

4*x+3 = 0

4*x+3 = 0 // - 3

4*x = -3 // : 4

x = -3/4

x in (-oo:-3/4) U (-3/4:+oo)

7/(4*x+3) = 2 // - 2

7/(4*x+3)-2 = 0

7/(4*x+3)+(-2*(4*x+3))/(4*x+3) = 0

7-2*(4*x+3) = 0

1-8*x = 0

(1-8*x)/(4*x+3) = 0

(1-8*x)/(4*x+3) = 0 // * 4*x+3

1-8*x = 0

1-8*x = 0 // - 1

-8*x = -1 // : -8

x = -1/(-8)

x = 1/8

x = 1/8

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