7/(4x-3)=2/(x+4)

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Solution for 7/(4x-3)=2/(x+4) equation: 



7/(4x-3)=2/(x+4)

We move all terms to the left:

7/(4x-3)-(2/(x+4))=0



Domain of the equation: (4x-3)!=0

We move all terms containing x to the left, all other terms to the right

4x!=3

x!=3/4

x!=3/4

x∈R





Domain of the equation: (x+4))!=0

x∈R



We calculate fractions


7x/((4x-3)*(x+4)))+(-(2*(4x-3))/((4x-3)*(x+4)))=0



We calculate terms in parentheses: -(2*(4x-3))/((4x-3)*(x+4))), so:

2*(4x-3))/((4x-3)*(x+4))

We multiply all the terms by the denominator


2*(4x-3))

We multiply parentheses

8x+

We add all the numbers together, and all the variables

8x

Back to the equation:

-(8x)



We add all the numbers together, and all the variables

-8x+7x/((4x-3)*(x+4)))+(=0

We multiply all the terms by the denominator


-8x*((4x-3)*(x+4)))+(+7x=0

We add all the numbers together, and all the variables

7x-8x*((4x-3)*(x+4)))+(=0

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