7/(6x-4)=9/(4x+6)

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Solution for 7/(6x-4)=9/(4x+6) equation: 



7/(6x-4)=9/(4x+6)

We move all terms to the left:

7/(6x-4)-(9/(4x+6))=0



Domain of the equation: (6x-4)!=0

We move all terms containing x to the left, all other terms to the right

6x!=4

x!=4/6

x!=2/3

x∈R





Domain of the equation: (4x+6))!=0

x∈R



We calculate fractions


28x/((6x-4)*(4x+6)))+(-(9*(6x-4))/((6x-4)*(4x+6)))=0



We calculate terms in parentheses: -(9*(6x-4))/((6x-4)*(4x+6))), so:

9*(6x-4))/((6x-4)*(4x+6))

We multiply all the terms by the denominator


9*(6x-4))

We multiply parentheses

54x+

We add all the numbers together, and all the variables

54x

Back to the equation:

-(54x)



We add all the numbers together, and all the variables

-54x+28x/((6x-4)*(4x+6)))+(=0

We multiply all the terms by the denominator


-54x*((6x-4)*(4x+6)))+(+28x=0

We add all the numbers together, and all the variables

28x-54x*((6x-4)*(4x+6)))+(=0

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