7/(u-4)=-(3)/(4u-16)+2

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Solution for 7/(u-4)=-(3)/(4u-16)+2 equation: 


D( u )

4*u-16 = 0

u-4 = 0

4*u-16 = 0

4*u-16 = 0

4*u-16 = 0 // + 16

4*u = 16 // : 4

u = 16/4

u = 4

u-4 = 0

u-4 = 0

u-4 = 0 // + 4

u = 4

u in (-oo:4) U (4:+oo)

7/(u-4) = 2-(3/(4*u-16)) // - 2-(3/(4*u-16))

7/(u-4)+3/(4*u-16)-2 = 0

(7*(4*u-16))/((u-4)*(4*u-16))+(3*(u-4))/((u-4)*(4*u-16))+(-2*(u-4)*(4*u-16))/((u-4)*(4*u-16)) = 0

7*(4*u-16)+3*(u-4)-2*(u-4)*(4*u-16) = 0

31*u-8*u^2+64*u-128-124 = 0

95*u-8*u^2-252 = 0

95*u-8*u^2-252 = 0

95*u-8*u^2-252 = 0

DELTA = 95^2-(-252*(-8)*4)

DELTA = 961

DELTA > 0

u = (961^(1/2)-95)/(-8*2) or u = (-961^(1/2)-95)/(-8*2)

u = 4 or u = 63/8

(u-4)*(u-63/8) = 0

((u-4)*(u-63/8))/((u-4)*(4*u-16)) = 0

((u-4)*(u-63/8))/((u-4)*(4*u-16)) = 0 // * (u-4)*(4*u-16)

(u-4)*(u-63/8) = 0

( u-4 )

u-4 = 0 // + 4

u = 4

( u-63/8 )

u-63/8 = 0 // + 63/8

u = 63/8

u in { 4} 

u = 63/8

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