7/(x+1)=9/(x-3)

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Solution for 7/(x+1)=9/(x-3) equation: 



7/(x+1)=9/(x-3)

We move all terms to the left:

7/(x+1)-(9/(x-3))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (x-3))!=0

x∈R



We calculate fractions


7x/((x+1)*(x-3)))+(-(9*(x+1))/((x+1)*(x-3)))=0



We calculate terms in parentheses: -(9*(x+1))/((x+1)*(x-3))), so:

9*(x+1))/((x+1)*(x-3))

We multiply all the terms by the denominator


9*(x+1))

We multiply parentheses

9x+

We add all the numbers together, and all the variables

9x

Back to the equation:

-(9x)



We add all the numbers together, and all the variables

-9x+7x/((x+1)*(x-3)))+(=0

We multiply all the terms by the denominator


-9x*((x+1)*(x-3)))+(+7x=0

We add all the numbers together, and all the variables

7x-9x*((x+1)*(x-3)))+(=0

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