7/(x+2)+11/(x-5)=7/(x+2)(x-5)

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Solution for 7/(x+2)+11/(x-5)=7/(x+2)(x-5) equation: 



7/(x+2)+11/(x-5)=7/(x+2)(x-5)

We move all terms to the left:

7/(x+2)+11/(x-5)-(7/(x+2)(x-5))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x-5)!=0

We move all terms containing x to the left, all other terms to the right

x!=5

x∈R





Domain of the equation: (x+2)(x-5))!=0

x∈R



We multiply parentheses ..

-(7/(+x^2-5x+2x-10))+7/(x+2)+11/(x-5)=0

We calculate fractions


(-(7*(x+2)*(x-5))/((+x^2-5x+2x-10))*(x+2)*x+(7*(+x^2-5x+2x-10))*x/((+x^2-5x+2x-10))*(x+2)*x+(11*(+x^2-5x+2x-10))*x/((+x^2-5x+2x-10))*(x+2)*x=0

We can not solve this equation

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