7/(x+3)=3/(x-1)

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Solution for 7/(x+3)=3/(x-1) equation: 



7/(x+3)=3/(x-1)

We move all terms to the left:

7/(x+3)-(3/(x-1))=0



Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R





Domain of the equation: (x-1))!=0

x∈R



We calculate fractions


7x/((x+3)*(x-1)))+(-(3*(x+3))/((x+3)*(x-1)))=0



We calculate terms in parentheses: -(3*(x+3))/((x+3)*(x-1))), so:

3*(x+3))/((x+3)*(x-1))

We multiply all the terms by the denominator


3*(x+3))

We multiply parentheses

3x+

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

-3x+7x/((x+3)*(x-1)))+(=0

We multiply all the terms by the denominator


-3x*((x+3)*(x-1)))+(+7x=0

We add all the numbers together, and all the variables

7x-3x*((x+3)*(x-1)))+(=0

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