7/(x+4)+1(/x-4)=0

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Solution for 7/(x+4)+1(/x-4)=0 equation: 



7/(x+4)+1(/x-4)=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R





Domain of the equation: x-4)!=0

x∈R



We calculate fractions


7x/(x^2+4x)+(1(*(x+4))/(x^2+4x)=0



We calculate terms in parentheses: +(1(*(x+4))/(x^2+4x), so:

1(*(x+4))/(x^2+4x

We multiply all the terms by the denominator


1(*(x+4))

Back to the equation:

+(1(*(x+4)))



We multiply all the terms by the denominator


7x+((1(*(x+4))))*(x^2+4x)=0



We calculate terms in parentheses: +((1(*(x+4))))*(x^2+4x), so:

(1(*(x+4))))*(x^2+4x

We add all the numbers together, and all the variables

4x+(1(*(x+4))))*(x^2

Back to the equation:

+(4x+(1(*(x+4))))*(x^2)

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