7/(x-2)+(1/x)=7/(x-2)

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Solution for 7/(x-2)+(1/x)=7/(x-2) equation: 


D( x )

x-2 = 0

x = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 0

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

7/(x-2)+1/x = 7/(x-2) // - 7/(x-2)

7/(x-2)-(7/(x-2))+1/x = 0

7/(x-2)-7*(x-2)^-1+1/x = 0

7/(x-2)-7/(x-2)+1/x = 0

(7*x)/(x*(x-2))+(-7*x)/(x*(x-2))+(1*(x-2))/(x*(x-2)) = 0

1*(x-2)+7*x-7*x = 0

x-2 = 0

(x-2)/(x*(x-2)) = 0

(x-2)/(x*(x-2)) = 0 // * x*(x-2)

x-2 = 0

x-2 = 0 // + 2

x = 2

x in { 2} 

x belongs to the empty set

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