7/(x-3)+1/x=7/x-3

Solution for 7/(x-3)+1/x=7/x-3 equation:

7/(x-3)+1/x=7/x-3

We move all terms to the left:

7/(x-3)+1/x-(7/x-3)=0


Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R



Domain of the equation: x!=0

x∈R



Domain of the equation: x-3)!=0

x∈R


We get rid of parentheses

7/(x-3)+1/x-7/x+3=0

We calculate fractions


7x/(x^2-3x)+(-7x+22)/(x^2-3x)+3=0

We multiply all the terms by the denominator


7x+(-7x+22)+3*(x^2-3x)=0

We multiply parentheses

3x^2+7x+(-7x+22)-9x=0

We get rid of parentheses

3x^2+7x-7x-9x+22=0

We add all the numbers together, and all the variables

3x^2-9x+22=0

a = 3; b = -9; c = +22;
Δ = b2-4ac
Δ = -92-4·3·22
Δ = -183
Delta is less than zero, so there is no solution for the equation