7/(x-4)=3

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Solution for 7/(x-4)=3 equation: 



7/(x-4)=3

We move all terms to the left:

7/(x-4)-(3)=0



Domain of the equation: (x-4)!=0

We move all terms containing x to the left, all other terms to the right

x!=4

x∈R



We multiply all the terms by the denominator


-3*(x-4)+7=0

We multiply parentheses

-3x+12+7=0

We add all the numbers together, and all the variables

-3x+19=0

We move all terms containing x to the left, all other terms to the right

-3x=-19

x=-19/-3

x=6+1/3

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