7/(x-5)=-35/(x+7)

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Solution for 7/(x-5)=-35/(x+7) equation: 


D( x )

x+7 = 0

x-5 = 0

x+7 = 0

x+7 = 0

x+7 = 0 // - 7

x = -7

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x in (-oo:-7) U (-7:5) U (5:+oo)

7/(x-5) = -35/(x+7) // + -35/(x+7)

7/(x-5)-(-35/(x+7)) = 0

7/(x-5)+35*(x+7)^-1 = 0

7/(x-5)+35/(x+7) = 0

(7*(x+7))/((x-5)*(x+7))+(35*(x-5))/((x-5)*(x+7)) = 0

7*(x+7)+35*(x-5) = 0

42*x-126 = 0

(42*x-126)/((x-5)*(x+7)) = 0

(42*x-126)/((x-5)*(x+7)) = 0 // * (x-5)*(x+7)

42*x-126 = 0

42*x-126 = 0 // + 126

42*x = 126 // : 42

x = 126/42

x = 3

x = 3

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