7/10(10k+20)=3(k-2

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Solution for 7/10(10k+20)=3(k-2 equation: 



7/10(10k+20)=3(k-2

We move all terms to the left:

7/10(10k+20)-(3(k-2)=0



Domain of the equation: 10(10k+20)!=0

k∈R



We multiply all the terms by the denominator


-((3(k-2))*10(10k+20)+7=0

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