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(7/10)*n-((5*(m-3))/5) = 2 // - 2
(7/10)*n-((5*(m-3))/5)-2 = 0
(7/10)*n-m-2+3 = 0
7/10*n-m+1 = 0
x należy do R
x in (-oo:+oo)
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