7/10u+3/2=2+3/5u

Solution for 7/10u+3/2=2+3/5u equation:

7/10u+3/2=2+3/5u

We move all terms to the left:

7/10u+3/2-(2+3/5u)=0


Domain of the equation: 10u!=0

u!=0/10

u!=0

u∈R



Domain of the equation: 5u)!=0

u!=0/1

u!=0

u∈R


We add all the numbers together, and all the variables

7/10u-(3/5u+2)+3/2=0

We get rid of parentheses

7/10u-3/5u-2+3/2=0

We calculate fractions


750u^2/200u^2+140u/200u^2+(-120u)/200u^2-2=0

We multiply all the terms by the denominator


750u^2+140u+(-120u)-2*200u^2=0

Wy multiply elements

750u^2-400u^2+140u+(-120u)=0

We get rid of parentheses

750u^2-400u^2+140u-120u=0

We add all the numbers together, and all the variables

350u^2+20u=0

a = 350; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·350·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*350}=\frac{-40}{700}
=-2/35
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*350}=\frac{0}{700}
=0
$