7/10x+6=1/2x

Solution for 7/10x+6=1/2x equation:

7/10x+6=1/2x

We move all terms to the left:

7/10x+6-(1/2x)=0


Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

7/10x-(+1/2x)+6=0

We get rid of parentheses

7/10x-1/2x+6=0

We calculate fractions


14x/20x^2+(-10x)/20x^2+6=0

We multiply all the terms by the denominator


14x+(-10x)+6*20x^2=0

Wy multiply elements

120x^2+14x+(-10x)=0

We get rid of parentheses

120x^2+14x-10x=0

We add all the numbers together, and all the variables

120x^2+4x=0

a = 120; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·120·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*120}=\frac{-8}{240}
=-1/30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*120}=\frac{0}{240}
=0
$