7/10x-8=1/5x-6

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Solution for 7/10x-8=1/5x-6 equation:



7/10x-8=1/5x-6
We move all terms to the left:
7/10x-8-(1/5x-6)=0
Domain of the equation: 10x!=0
x!=0/10
x!=0
x∈R
Domain of the equation: 5x-6)!=0
x∈R
We get rid of parentheses
7/10x-1/5x+6-8=0
We calculate fractions
35x/50x^2+(-10x)/50x^2+6-8=0
We add all the numbers together, and all the variables
35x/50x^2+(-10x)/50x^2-2=0
We multiply all the terms by the denominator
35x+(-10x)-2*50x^2=0
Wy multiply elements
-100x^2+35x+(-10x)=0
We get rid of parentheses
-100x^2+35x-10x=0
We add all the numbers together, and all the variables
-100x^2+25x=0
a = -100; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-100)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-100}=\frac{-50}{-200} =1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-100}=\frac{0}{-200} =0 $

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