7/12y=2+4/y

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Solution for 7/12y=2+4/y equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(7/12)*y = 4/y+2 // - 4/y+2

(7/12)*y-(4/y)-2 = 0

(7/12)*y-4*y^-1-2 = 0

7/12*y^1-4*y^-1-2*y^0 = 0

(7/12*y^2-2*y^1-4*y^0)/(y^1) = 0 // * y^2

y^1*(7/12*y^2-2*y^1-4*y^0) = 0

y^1

(7/12)*y^2-2*y-4 = 0

(7/12)*y^2-2*y-4 = 0

DELTA = (-2)^2-(-4*4*(7/12))

DELTA = 40/3

DELTA > 0

y = ((40/3)^(1/2)+2)/(2*(7/12)) or y = (2-(40/3)^(1/2))/(2*(7/12))

y = 6/7*((40/3)^(1/2)+2) or y = 6/7*(2-(40/3)^(1/2))

y in { 6/7*(2-(40/3)^(1/2)), 6/7*((40/3)^(1/2)+2)}

y in { 6/7*(2-(40/3)^(1/2)), 6/7*((40/3)^(1/2)+2) }

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