7/16=2(3z+1)/9

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Solution for 7/16=2(3z+1)/9 equation: 



7/16=2(3z+1)/9

We move all terms to the left:

7/16-(2(3z+1)/9)=0

We calculate fractions


(-(2(3z+1)*16)/()+()/()=0



We calculate terms in parentheses: +(-(2(3z+1)*16)/()+()/(), so:

-(2(3z+1)*16)/()+()/(

We add all the numbers together, and all the variables

-(2(3z+1)*16)/()+1

We multiply all the terms by the denominator


-(2(3z+1)*16)+1*()



We calculate terms in parentheses: -(2(3z+1)*16), so:

2(3z+1)*16

We multiply parentheses

96z+32

Back to the equation:

-(96z+32)



We add all the numbers together, and all the variables

-(96z+32)

We get rid of parentheses

-96z-32

Back to the equation:

+(-96z-32)



We get rid of parentheses

-96z-32=0

We move all terms containing z to the left, all other terms to the right

-96z=32

z=32/-96

z=-1/3

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