7/2(4n-8)+6=4/3(9n-12)

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Solution for 7/2(4n-8)+6=4/3(9n-12) equation: 



7/2(4n-8)+6=4/3(9n-12)

We move all terms to the left:

7/2(4n-8)+6-(4/3(9n-12))=0



Domain of the equation: 2(4n-8)!=0

n∈R





Domain of the equation: 3(9n-12))!=0

n∈R



We calculate fractions


(21n9/(2(4n-8)*3(9n-12)))+(-8n4/(2(4n-8)*3(9n-12)))+6=0



We calculate terms in parentheses: +(21n9/(2(4n-8)*3(9n-12))), so:

21n9/(2(4n-8)*3(9n-12))

We multiply all the terms by the denominator


21n9

We add all the numbers together, and all the variables

21n^9

We do not support enpression: n^9

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