7/2(4x-4)=8/3(-3x+3)

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Solution for 7/2(4x-4)=8/3(-3x+3) equation: 



7/2(4x-4)=8/3(-3x+3)

We move all terms to the left:

7/2(4x-4)-(8/3(-3x+3))=0



Domain of the equation: 2(4x-4)!=0

x∈R





Domain of the equation: 3(-3x+3))!=0

x∈R



We calculate fractions


(21x(-)/(2(4x-4)*3(-3x+3)))+(-16x4/(2(4x-4)*3(-3x+3)))=0



We calculate terms in parentheses: +(21x(-)/(2(4x-4)*3(-3x+3))), so:

21x(-)/(2(4x-4)*3(-3x+3))

We add all the numbers together, and all the variables

21x0/(2(4x-4)*3(-3x+3))

We multiply all the terms by the denominator


21x0

We add all the numbers together, and all the variables

21x

Back to the equation:

+(21x)





We calculate terms in parentheses: +(-16x4/(2(4x-4)*3(-3x+3))), so:

-16x4/(2(4x-4)*3(-3x+3))

We multiply all the terms by the denominator


-16x4

We add all the numbers together, and all the variables

-16x^4

We do not support expression: x^4

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