7/2(x-3)=4/5(x+10)

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Solution for 7/2(x-3)=4/5(x+10) equation: 



7/2(x-3)=4/5(x+10)

We move all terms to the left:

7/2(x-3)-(4/5(x+10))=0



Domain of the equation: 2(x-3)!=0

x∈R





Domain of the equation: 5(x+10))!=0

x∈R



We calculate fractions


(35xx/(2(x-3)*5(x+10)))+(-8xx/(2(x-3)*5(x+10)))=0



We calculate terms in parentheses: +(35xx/(2(x-3)*5(x+10))), so:

35xx/(2(x-3)*5(x+10))

We multiply all the terms by the denominator


35xx

Back to the equation:

+(35xx)





We calculate terms in parentheses: +(-8xx/(2(x-3)*5(x+10))), so:

-8xx/(2(x-3)*5(x+10))

We multiply all the terms by the denominator


-8xx

Back to the equation:

+(-8xx)



We get rid of parentheses

35xx-8xx=0

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