7/2(y-1)=4+3y

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Solution for 7/2(y-1)=4+3y equation: 



7/2(y-1)=4+3y

We move all terms to the left:

7/2(y-1)-(4+3y)=0



Domain of the equation: 2(y-1)!=0

y∈R



We add all the numbers together, and all the variables

7/2(y-1)-(3y+4)=0

We get rid of parentheses

7/2(y-1)-3y-4=0

We multiply all the terms by the denominator


-3y*2(y-1)-4*2(y-1)+7=0

Wy multiply elements

-6y^2(y-8y(y+7=0

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